by Peter

(Hobart, Tasmania, Australia)

Assume the log is a cylinder (say 20 cm radius) and the core that is left over is a cylinder (or close to it) of 5cm radius. What length of veneer could be produced off a rotary peeler machine where the thickness of veneer was 5mm.

The simple solution would be to measure circumference of a number of cylinders each with radius reduced by 5mm until you got to the core. But there must be a more mathematically correct way of doing this.

I want a formula so that I can plug in the log radius, the core radius and the veneer thickness so I can get a solution to generate the length produced.

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