by Tom
(Malaysia)

The sum of the 1st n positive integers is given by 1/2n(n + 1).

a)Given that the sum 14 + 15 + 16 +.... + K is 539.

i)form a quadratic equation in terms of k.
ii) find value of k.

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 Sep 30, 2015 Rating Get My Education NEW by: Anonymous Amazing, this is great as you want to learn more, I invite to good colleges This is my page.

 Jul 20, 2011 Rating sudhanshu.cochin@gmail.com by: sudhanshu kumar The sum of the 1st n positive integers is given by (1/2)*n(n + 1). (i) sum of (k-13)terms of series 14,15.....,k (1/2)* (k-13)(k+14) =539 => k^2 + k - 182 = 1078 => k^2 + k - 1260 =0 (ii) now factorize... k^2 +36k -35k -1260=0 => (k+36)(k-35)=0 so, k = 35 , because k = -36 not possible.

 Jul 19, 2011 Rating Solution by: Andrew Cronie i) k^2 + k - 1260 = 0 ii) k = 35

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